Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(X, Y), Z) -> f2(X, f2(Y, Z))
f2(X, f2(Y, Z)) -> f2(Y, Y)
Q is empty.
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f2(f2(X, Y), Z) -> f2(X, f2(Y, Z))
f2(X, f2(Y, Z)) -> f2(Y, Y)
Q is empty.
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F2(X, f2(Y, Z)) -> F2(Y, Y)
F2(f2(X, Y), Z) -> F2(X, f2(Y, Z))
F2(f2(X, Y), Z) -> F2(Y, Z)
The TRS R consists of the following rules:
f2(f2(X, Y), Z) -> f2(X, f2(Y, Z))
f2(X, f2(Y, Z)) -> f2(Y, Y)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ DependencyPairsProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F2(X, f2(Y, Z)) -> F2(Y, Y)
F2(f2(X, Y), Z) -> F2(X, f2(Y, Z))
F2(f2(X, Y), Z) -> F2(Y, Z)
The TRS R consists of the following rules:
f2(f2(X, Y), Z) -> f2(X, f2(Y, Z))
f2(X, f2(Y, Z)) -> f2(Y, Y)
Q is empty.
We have to consider all minimal (P,Q,R)-chains.